SOLUTION: (3^2 - 2^2)^3 + 42 � 6 x 3^2 - 9 (9-4)^3 + 42 / 6 x 9 - 9 125 + 42 / 54 - 9 125 + 0.77777777777777777778 - 9 116.7777777777777 The problem is that the answer is suppose to b

Question 759128: (3^2 - 2^2)^3 + 42 � 6 x 3^2 - 9
(9-4)^3 + 42 / 6 x 9 - 9
125 + 42 / 54 - 9
125 + 0.77777777777777777778 - 9
116.7777777777777
The problem is that the answer is suppose to be 179 and I am following PEMDAS and I do not reach that answer
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(3^2 - 2^2)^3 + 42 � 6 x 3^2 - 9
= (9 - 4)^3 + 7 x 9 - 9
= 125 + 63 - 9
= 179
================
(3^2 - 2^2)^3 + 42 � 6 x 3^2 - 9
(9-4)^3 + 42 / 6 x 9 - 9
125 + 42 / 54 - 9 ************* ************
125 + 0.77777777777777777778 - 9
116.7777777777777

RELATED QUESTIONS
42/2�(12+9)= (answered by rfer)

2=6 3=12 4=20 5=30 6=42 9=? (answered by solver91311)

Factor each expression completely. 1. 12x2 + 6x + 18 3(2x2 + x + 3)... (answered by jim_thompson5910)

[54 - 3(2 + 4)] �... (answered by tommyt3rd)

(6-9)^2/3 (answered by user_dude2008)

The length of a rectangular jewelry box in 3 inches more than twice the width. The... (answered by rfer)

I have two questions. solve the equation. 1/x+7 + 5/x+6 = -1/x^2+13x+42. The second... (answered by Fombitz)

9+3-2+4=6 (answered by lenny460)

9+3-2+4=6 (answered by Alan3354)