SOLUTION: 5x²+x-7=0

Algebra.Com
Question 735079: 5x²+x-7=0
Answer by tommyt3rd(5050)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=141 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.08743420870379, -1.28743420870379. Here's your graph:
RELATED QUESTIONS

x^2-5x-7<0 Help!... (answered by longjonsilver)
solve... (answered by Fombitz)
(x^7 + 5x)(x^7-5x) Multiply (answered by sealy123)
X^3-5X=0 (answered by MathLover1)
Directions: Solve each equation. State the number and type of roots. Problem: -5x-7=0 I (answered by stanbon)
(5x+3)(x+7) (answered by checkley75)
-5x(x + 2y - 7) (answered by edjones)
5x-17=-x+7 (answered by richard1234)
7^(x-2)=5x (answered by stanbon)