SOLUTION: ((2x-14)/2x)*((6x^2)/X^2-49))= I have broken the question down to: ((2(x-7)/2x))*((3x*3x)/(x(x-49)) and this is where I am lost.....

SOLUTION: ((2x-14)/2x)((6x^2)/X^2-49))= I have broken the question down to: ((2(x-7)/2x))((3x*3x)/(x(x-49)) and this is where I am lost.....

Question 7128: ((2x-14)/2x)*((6x^2)/X^2-49))=
I have broken the question down to:
((2(x-7)/2x))*((3x*3x)/(x(x-49))
and this is where I am lost.....
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let's see:
Simplify:
Your first step was ok, factor out the 2 in the first fraction. The second part was not quite right. In the second fraction, you can factor the binomial in the denominator:

In the first fraction, cancel the 2's, then cancel the (x-7)'s, finally, cancel an x from the denominator of the first fraction and the numerator of the second fraction.
= and this is as far as you can go.

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