SOLUTION: I am not sure if I am doing this question right, Can someone help me? My question is multiply, 3xyz^2 2y ------ by ----- 6y^4 xz^4 I think the answer is x^2

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: I am not sure if I am doing this question right, Can someone help me? My question is multiply, 3xyz^2 2y ------ by ----- 6y^4 xz^4 I think the answer is x^2      Log On


   

Question 6201: I am not sure if I am doing this question right, Can someone help me? My question is multiply,
3xyz^2 2y
------ by -----
6y^4 xz^4
I think the answer is
x^2
---------
3y^2 z^2
Am I right?
Answer by Abbey(339) About Me  (Show Source):
You can put this solution on YOUR website!
because everything is being multiplied (and not added or subtracted) you can take every cancellation opportunity:
%283xy%5E2%2A2y%29%2F%286Y%5E4xz%5E4%29
so the (3*2) in the numerator cancels with the 6 in the denominator:
%28xy%5E2%2Ay%29%2F%28y%5E4xz%5E4%29
then the x in the numerator cancels with the x in the denominator:
%28y%5E2%2Ay%29%2F%28y%5E4z%5E4%29
then the (y^2*y) in the numerator will cancel with three of the Y's in the denominator:
1%2F%28yz%5E4%29