# SOLUTION: Hello can you solve me a partial fractions equation please its (x²+9x+8)/(x²+x-6)

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 Question 602449: Hello can you solve me a partial fractions equation please its (x²+9x+8)/(x²+x-6)Answer by AnlytcPhil(1277)   (Show Source): You can put this solution on YOUR website!``` To break into partial fractions, the numerator must have a smaller degree than the denominator. If the numerator has the same or larger degree, we must first divide by long division: 1 x² + x - 6)x² + 9x + 8 x² + x - 6 8x + 14 = 1 + So we break into partial fractions and add what we get to the 1 above: = = + 8x + 14 = A(x - 2) + B(x + 3) This must be an identity for all x, so we substitute 2 for x to make the first term on the right become 0: 8(2) + 14 = A(2 - 2) + B(2 + 3) 16 + 14 = 5B 30 = 5B 6 = B Substitute -3 for x to make the second term on the right become 0: 8(-3) + 14 = A(-3 - 2) + B(-3 + 3) -24 + 14 = -5A -10 = -5A 2 = A = + Now we add that to 1 and get = 1 + + Edwin```