SOLUTION: 64(3/16+5/6-1/4+1/2)

Algebra.Com
Question 586716: 64(3/16+5/6-1/4+1/2)
Answer by ad_alta(240)   (Show Source): You can put this solution on YOUR website!
1) 64(3/16+5/6-1/4+1/2) [distribute]
2) 12+160/3-16+32 [simplify]
3) 28+160/3 [common denominator]
4) 244/3

RELATED QUESTIONS

explain an error pattern; 13/35=1/5, 27/73=2/3,... (answered by richard1234)
find the sum of the geometric series 6 [SUM] 2^n n=1 n=1 2^1=2 n=2 2^2=4 n=3 (answered by jim_thompson5910)
explain an error pattern in each of the following A. 13/35=1/5, 27/73= 2/3, 16/64= 1/4 (answered by richard1234)
solve the following; (-1/64)^-1/3 (16/81)^-3/4 (1/Radical32)^-2/5 -(1/25)^-4/3... (answered by ewatrrr)
16/4 + {5*6 -... (answered by solver91311)
how do i solve 64(3/16+5/8-1/4+1/2) thanks for ur... (answered by mananth)
1. 2x^2+10x+12 Factor completely 2.x^2+8x=-16 3.x^2-16=0 4. x^2-16x=-64 5. (answered by ankor@dixie-net.com)
Find the sum of -16 + 4 - 1 + ... Does not exist 64/5 -64/5... (answered by fractalier)
exponential equations 4^3x-3=8^4x-4, 9^-X-5=27^6x-10, 125^3x-4=25^4x+2,... (answered by ewatrrr)