SOLUTION: i do not understand this problem at all and i dont understand what im suppose to do on it... can you please explain to me? the problem is: A brick is 1 7/8 in. high Mortar that is

Question 584363: i do not understand this problem at all and i dont understand what im suppose to do on it... can you please explain to me? the problem is: A brick is 1 7/8 in. high Mortar that is 3/8 in. thick is spread on each row of bricks. How many rows of bricks are needed to reach the top of a 7 1/2-ft doorway? Please try to respond to this for me by tomorrow... my homework is due tomorrow and I really want to be able to know how to do this. Thank you so much for taking your time.
Found 2 solutions by richwmiller, solver91311:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
how many rows of 1 7/8 in plus 3/8 in do you need to make a wall 7.5 feet high.
(1 7/8 + 3/8)=1 10/8= 2 2/8=2.25 inches
7.5 feet =7.5 *12 inches=90 inches
90/2.25=40 rows
You need at least forty rows of brick and mortar to reach the 7 1/2 ft doorway

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

inches per row.

, so seven and a half feet is 90 inches.

How many times will inches fit into 90 inches? Divide 90 by 2.25.

This assumes you lay the first course with no mortar beneath it (very dumb idea) or there is no layer of mortar on top of the last row of bricks.

John

My calculator said it, I believe it, that settles it

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