SOLUTION: [[4x+6]/[2x+8]] how would you simplify a fraction like this or like [8r^2-8r] / [2r-2] i dont know if it would be right to simplify but changing [for the first equation] 6 to 3 an

Question 473358: [[4x+6]/[2x+8]] how would you simplify a fraction like this or like [8r^2-8r] / [2r-2]
i dont know if it would be right to simplify but changing [for the first equation] 6 to 3 and 8 to 2 VERY confused
Thank you!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[[4x+6]/[2x+8]] how would you simplify a fraction like this
---
You need to factor the numerator and the denominator:
[2(2x+3)]/[2(x+4)]
Then cancel any factor that is common to the numerator and the denominator:
= (2x+3)/(x+4)
=======================
[8r^2-8r] / [2r-2]
----
[8r(r^2-1)] / [2(r-1)]
----
= [8r(r-1)(r+1)]/[2(r-1)]
----
Cancel the common 2 and the common r-1 factors to get:
---
= [4r(r+1)]
====
Cheers,
Stan H.
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