SOLUTION: I am trying to show the result of adding two fractions. x=times and /= divide What are the steps to show that u x i/2pi x (D+d)+ u x i/2pi x (D-d) is equalt to u x i x D/pi(D

Question 44613: I am trying to show the result of adding two fractions.
x=times and /= divide
What are the steps to show that
u x i/2pi x (D+d)+ u x i/2pi x (D-d) is equalt to u x i x D/pi(D sq -d sq)
Hope you can help
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
u x i/2pi x (D+d)+ u x i/2pi x (D-d) is equalt to u x i x D/pi(D sq -d sq)
ui/(2pi(D+d)) + ui/(2pi(D-d))
LCD = 2pi(D^2-d^2)
Write each fraction over the LCD, as follows:
=ui(D-d)/LCD + ui(D+d)/LCD
=Add the numerators and write the sum over the LCD, as follows:
=[uiD-uid+uiD+uid]/LCD
=2uiD/[2pi(D^2-d^2)
= uiD/[(pi)(D^2-d^2)
I am assuming your pi is not p*i but rather the number pi=3.1459...
Cheers,
Stan H.

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