SOLUTION: I really need Help!!! could someone Kindly Help me:) This is my Question: Find three consecutive odd integers such that twice the sum of the smaller two integers is 25 more

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The first integer will be x, The second will be x+2, the third x+4.
From the information given we know that 2 times the sum of the two smaller integers OR
2(x+(x+2)). equals 25 more than 3 times the largest OR (25+3(x+4)). SO we combine these into an equation.
Now solve for x starting with combining like terms.
Subtract 3x from both sides and subtract 4 from both sides.


So the first integer is 33. Therefore the second integer is 33+2=35.
and the third integer is 33+4=37.
Three integers: 33, 35, 37