SOLUTION: please ! could you help me in these problems
1) The denominator of a fraction is three more than the numerator. If the numerator is doubled and the denominator is increased
Algebra.Com
Question 33678This question is from textbook numeric Fraction
: please ! could you help me in these problems
1) The denominator of a fraction is three more than the numerator. If the numerator is doubled and the denominator is increased by nine, the resulting fraction is equal to ½. What is the original fraction?
2) The denominator of a fraction is three more than numerator. If the numerator is tripled and the denominator is increased by 17, the resulting fraction is ½. What is the original fraction?
3) Bob, Celia, Sam and Daniel contributed money to buy their boss a retirement gift. Sam and Daniel each gave the same amount of money. Celia gave $12 more than Daniel. Bob gave half as much as Celia gave. If the four workers gave a total of $81, how much did Sam give?
From your faithfully student
This question is from textbook numeric Fraction
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
1) The denominator(DR) of a fraction is three more than the numerator(NR). If the numerator is doubled and the denominator is increased by nine, the resulting fraction is equal to ½. What is the original fraction?
LET NR =N
3 MORE =N+3=DR...SO FRACTION IS N/(N+3)
NR IS DOUBLED...WE GET 2N
DR INCREASED BY 9...WE GET DR+9=N+3+9=N+12
NEW FRACTION=2N/(N+12)=1/2
2*2N=N+12
4N-N=12.....3N=12.....N=4
HENCE ORIGINAL FRACTION =N/(N+3)=4/7
2) The denominator of a fraction is three more than numerator. If the numerator is tripled and the denominator is increased by 17, the resulting fraction is ½. What is the original fraction?
PROCEDING IN SAME WAY AS ABOVE
ORIGINAL FRACTION =N/(N+3)...AND
3N/(N+3+17)=1/2
2*3N=N+20
6N-N=20
N=4
ORIGINAL FRACTION =4/7
3) Bob, Celia, Sam and Daniel contributed money to buy their boss a retirement gift. Sam and Daniel each gave the same amount of money. Celia gave $12 more than Daniel. Bob gave half as much as Celia gave. If the four workers gave a total of $81, how much did Sam give?
LSET SAM GIVE =S
DANIEL GAVE =S
12 MORE =S+12=CELIA GAVE
HALF THIS =(S+12)/2=BOB GAVE
TOTAL GIVEN =S+S+S+12+(S+12)/2=81
{2(3S+12)+S+12}=2*81=162
6S+24+S+12=162
7S=162-36=126
S=126/7=18
HENCE SAM GAVE 18 $
RELATED QUESTIONS
Please ! help me about this three word problems. I ca not work out.
(1) The... (answered by mukhopadhyay)
Please help me find the original fraction- The denominator of a fraction is five more... (answered by josgarithmetic,ewatrrr)
please help solve:
The denominator of a fraction is 1 more than the numerator. If both... (answered by josgarithmetic,greenestamps)
Good day to you. My daughter is having a problem with algebra word problems, can you... (answered by ReadingBoosters,Alan3354)
the denominator of the fraction is 2 more than the numerator. if 1 is subtracted from... (answered by Fombitz)
Hello, can you please help me solve this problems:
1.) One number is 3 more than the... (answered by oscargut,ankor@dixie-net.com)
The denominator of a fraction is 1 more than the numerator. If the numerator is decreased (answered by mananth)
Please help me!
The denominator of a fraction is by 3 larger than the numerator. If the (answered by jim_thompson5910)
The numerator of a fraction is seven more than twice the denominator. The value of the... (answered by checkley71,Earlsdon,solver91311)