SOLUTION: THE DIGIT AT TEN,S PLACE OF A TWO DIGIT NUMBER IS TWICE THE DIGIT AT THE ONE,S PLACE . IF THE SUM OF THIS NUMBER AND NUMBER FORMED BY REVERSING THE DIGIT IS 66. FIND THE NUMBERS?
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Question 319076: THE DIGIT AT TEN,S PLACE OF A TWO DIGIT NUMBER IS TWICE THE DIGIT AT THE ONE,S PLACE . IF THE SUM OF THIS NUMBER AND NUMBER FORMED BY REVERSING THE DIGIT IS 66. FIND THE NUMBERS?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let AB be your digit or numerically 10*A+B.
The reverse digit number is BA or numerically 10*B+A.
1.
.
.
2.
Substitute eq. 1 into eq. 2,
Then from eq. 1,
.
.
.
The original number is 24, the reverse number is 42.
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