SOLUTION: I need to solve this by losing the fraction
2n-3 over 2 = 3/4
Algebra.Com
Question 298625: I need to solve this by losing the fraction
2n-3 over 2 = 3/4
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2n-3 / 2= 3/4
eliminate the denominator on the left hand side of the equation by multiplying by 2
2n-3 / 2 * 2 = 3/4 * 2
2n-3 = 3/2
similarly for right hand side of the equation multiply by 2
2(2n-3) = 3/2 * 2
4n-6=3
4n=6+3
4n=9
n=9/4
---------------
2n-3 / 2= 3/4
OR later you could just do it this way
4(2n-3) = 2*3
8n-12 = 6
8n=6+12
8n=18
n=18/8
n= 9/4
RELATED QUESTIONS
I've been working on this problem for 2 hours, and I would like some help.
I need to... (answered by ptaylor)
3n over 4 - 1 over 3 = 2n-1 over 6
multiplied each fraction by 12 and cancelled... (answered by Edwin McCravy,Mathtut)
OK, I need to find out why 3 divided by 4 + Pie/ 2Pie is supposed to be equal to 2/3.... (answered by Fermat,Alan3354)
Please help me solve this equation: 2=n-(2n+3). I need to find the value of n. The book (answered by longjonsilver,scoop,shorty33353)
How to compute the sum of this series?... (answered by greenestamps)
I have the problem:
1 1
__ - __
4n 2
*OVER*
n 1
__- ___
6 24n... (answered by ankor@dixie-net.com)
This is the equation:
((( (2 over x+3) + (1 over x) = (4 over 3x) )))
When I say... (answered by sudhanshu_kmr)
I am struggling with this problem and do not know how to solve it. Please help if you... (answered by Edwin McCravy)
this is a complex fraction that I have attempted to solve but I am unable. Please help.... (answered by rapaljer)