SOLUTION: 5(2q+3)p-4(p-1)=

SOLUTION: 5(2q+3)p-4(p-1)=

Algebra.Com

Question 274850: 5(2q+3)p-4(p-1)=
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
5(2q+3)p-4(p-1)=10pq+15p-4p+4=10pq+11p+4
RELATED QUESTIONS
How would I factor this? 12(p+2q)^4-40(p+2q)^3+12(p+2q)^2 Thank... (answered by jim_thompson5910)

((p^2q^3)(m^4p^3q^3)(-2pm^3q^-3))/-m^2q^4 (answered by Fombitz)

(4p^2q)(p^2q^3) simplify thank... (answered by mastermath)

-4(3-p)>5(p+1) (answered by rfer,robertb)

5+3(p-4)=2(p+1) (answered by Okeke_Christian)

(-8... (answered by AnlytcPhil)

The question is (p^2q^2/p^-4q^5)^-3. Can you... (answered by ankor@dixie-net.com,Fombitz)

p^3q^4 ________ p^2q^3 Use the quotient rule and... (answered by Alan3354)

please help me solve this 2q-p=-4----------(i)... (answered by josgarithmetic)