SOLUTION: (-3y^2+3y+8)/((y-3)(3y+1))=-(〖3y〗^2-3y-8)/((y-3)(3y+1)) is correct?
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Question 255103: (-3y^2+3y+8)/((y-3)(3y+1))=-(〖3y〗^2-3y-8)/((y-3)(3y+1)) is correct?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
No the 3 does not get squared.
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