SOLUTION: write a fraction expression equivalent to 2/3 with a denominator of 12. I know the answer, i dont how to come about the answer. please help

Question 254480: write a fraction expression equivalent to 2/3 with a denominator of 12. I know the answer, i dont how to come about the answer. please help

Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write a fraction expression equivalent to 2/3 with a denominator of 12. I know the answer, i dont how to come about the answer.
--------------------------
Ask yourself, "What would I need to multiply 3 by to get 12 in
the denominator?".
---
The answer would be "4".
----
So you need to multiply numerator and denominator by 4 to get:
---
(2/3)(4/4) = 8/12
==========================
Cheers,
Stan H.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
so what answer did you find in the book?
2/3=x/12
solve for x
cross multiply OR
multiply both sides by 12 and both sides by 3
24=3x
8=x
RELATED QUESTIONS
Find the sum of each of the following infinite series. If a series does not have a sum... (answered by rapaljer)
find the improper fraction with a denominator of 6 that is equivalent to 5 1/2 (answered by nyc_function)
I a having toubles figuring out how to find equivalent fractions so the fraction in each... (answered by KMST)
Decompose into a partial fraction 6x^2-15x+16/x^3-3x^2+4x I know to start I need to (answered by stanbon)
12. The sum of numerator and denominator of a fraction is 8. I 3 is added to both... (answered by KMST)
I dont know how to do this; Write an algebraic expression for: two thirds of the square... (answered by stanbon)
I am having a difficult time with this question, its been 10 years since needing to do... (answered by solver91311)
I am trying to re-write the following expression using negative exponents: x^2/y^2... (answered by sdmmadam@yahoo.com,longjonsilver)
Rationalizing the Denominator Numerator is 6 Denominator is 2 times the radical... (answered by ankor@dixie-net.com)