SOLUTION: 2zx2y=18 where x=1,z=y

SOLUTION: 2zx2y=18 where x=1,z=y

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Question 206976: 2zx2y=18 where x=1,z=y
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
2zx2y=18,,,but z=y,,,x=1,
.
2(y)(1)2y=18
.
4y^2 =18
.
y^2 =18/4 =4.5
.
y= +/-2.12
.

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