SOLUTION: I guess algebra just really isnt my strongest point, could someone help me here, I totally didnt understand this one; If y varies directly as x and inversely as z^2, and y= 3 when

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Question 199482: I guess algebra just really isnt my strongest point, could someone help me here,
I totally didnt understand this one; If y varies directly as x and inversely as z^2, and y= 3 when x=2 and z=4, what is the value of x when y=9 and z=4?
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


If varies directly as and inversely as , then you can say:



So if when and , then you can say:



Solve for :







Now you can say:



And if you want to know the value of when and , then just make the substitutions:



And solve for .

John
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