SOLUTION: I'm trying to find for what x and y value that this inequality is true: ln x - ln y < (x^2-y^2)/2xy I've simplified it to ln (x - y)

SOLUTION: I'm trying to find for what x and y value that this inequality is true: ln x - ln y < (x^2-y^2)/2xy I've simplified it to ln (x - y) < (x^2-y^2)/2xy I can't remember where

Question 18431: I'm trying to find for what x and y value that this inequality is true:
ln x - ln y < (x^2-y^2)/2xy
I've simplified it to ln (x - y) < (x^2-y^2)/2xy
I can't remember where to go from here. I'm hoping you can point me in the right direction!
Thanks!
Answer by kelljohn19(2) (Show Source): You can put this solution on YOUR website!
(x - y) < (x^2-y^2)/2xy
RELATED QUESTIONS
I'm trying to find the inverse of the following function: f(x)=ln(x-2)+1. Here's what I (answered by lwsshak3)

how do I solve... (answered by stanbon)

y=-ln(x+2) (answered by longjonsilver)

2 ln x + 3 ln... (answered by ankor@dixie-net.com)

ln x^2+3 ln... (answered by Alan3354)