SOLUTION: Solve for X
43. (x - 6)^2 = 2x - 9x + 38
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Question 171818: Solve for X
43. (x - 6)^2 = 2x - 9x + 38
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation
Combine like terms.
FOIL
Subtract 7x from both sides. Add 38 to both sides.
Combine like terms.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in , , and
Negate to get .
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
or Break up the expression.
So the answers are or
which approximate to or
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(x-6)^2=2x-9x+38
x^2-12x+36=-7x+38
x^2-12x+7x+36-38=0
x^2-5x-2=0
Solving this equation we get irrational roots.
IF you meant:
(x-6)^2=2x^2-9x+38 Then:
x^2-12x+36=2x^2-9x+38
x^2-2x^2-12x+9x+36-38=0
-x^2-3x-2=0 multiply by -1:
x^2+3x+2=0
(x+2)(x+1)=0
x+2=0
x=-2 ans
x+1=0
x=-1 ans.
Proofs:
(-2-6)^2=2*-2^2-9*-2+38
-8*2=2*4+18+38
64=8+18=38
64=64
(-1-6)^2=2*-1^2-9*-1+38
-7^2=2*1+9+38
49=2+9+38
49=49
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