SOLUTION: Solve for X 43. (x - 6)^2 = 2x - 9x + 38

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Question 171818: Solve for X
43. (x - 6)^2 = 2x - 9x + 38

Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given equation


Combine like terms.


FOIL


Subtract 7x from both sides. Add 38 to both sides.


Combine like terms.


Notice we have a quadratic equation in the form of where , , and


Let's use the quadratic formula to solve for x


Start with the quadratic formula


Plug in , , and


Negate to get .


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


or Break up the expression.


So the answers are or


which approximate to or

Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
(x-6)^2=2x-9x+38
x^2-12x+36=-7x+38
x^2-12x+7x+36-38=0
x^2-5x-2=0
Solving this equation we get irrational roots.
IF you meant:
(x-6)^2=2x^2-9x+38 Then:
x^2-12x+36=2x^2-9x+38
x^2-2x^2-12x+9x+36-38=0
-x^2-3x-2=0 multiply by -1:
x^2+3x+2=0
(x+2)(x+1)=0
x+2=0
x=-2 ans
x+1=0
x=-1 ans.
Proofs:
(-2-6)^2=2*-2^2-9*-2+38
-8*2=2*4+18+38
64=8+18=38
64=64
(-1-6)^2=2*-1^2-9*-1+38
-7^2=2*1+9+38
49=2+9+38
49=49

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