SOLUTION: Which ordered pair is a solution of the system of equations? (x,y) y=3x+1 y=5x-3 A. (2,3) B. (0,1) C. (1,2) D. (2,7)

Question 151611: Which ordered pair is a solution of the system of equations? (x,y)
y=3x+1 y=5x-3
A. (2,3) B. (0,1) C. (1,2) D. (2,7)
Found 3 solutions by jojo14344, mangopeeler07, jim_thompson5910:
Answer by jojo14344(1513)   (Show Source): You can put this solution on YOUR website!
Equating the 2 eqns;

for y,
y=3*2+1, ------>
(2,7)
Answer: D
Thank you,
Jojo
Answer by mangopeeler07(462)   (Show Source): You can put this solution on YOUR website!
plug in the solutions for A, B, C, and D.

y=3x+1
y=5x-3

A. (2,3)

3=3(2)+1
3=5(2)-3
WRONG

Answer: not A
-------------------------------------------------------------------------
B. (0,1)

1=3(0)+1
1=5(0)-3
WRONG

Answer: not A or B
--------------------------------------------------------------------------
C. (1,2)

2=3(1)+1
2=5(1)-3
WRONG

Answer: not A, B, or C
---------------------------------------------------------------------------
At this point, we know the answer is D, but let's do it anyway.
D. (2,7)

7=3(2)+1
7=5(2)-3
RIGHT

Answer: D
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
In order to find the answer, let's check all of the possible answers (note: an alternative is to solve the system)

A)

Let's see if (2,3) is a solution.

Start with the first equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is not true, this means that (2,3) is not a solution.

Let's see if (2,3) is a solution.

Start with the second equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is not true, this means that (2,3) is not a solution.

Since at least one of the equations of the system is false, this means that (2,3) is not a solution. Remember, a solution must satisfy all of the equations in the system.

B)

Let's see if (0,1) is a solution.

Start with the first equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is true, this means that (0,1) is a solution.

Let's see if (0,1) is are a solution.

Start with the second equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is not true, this means that (0,1) is not a solution.

Since at least one of the equations of the system is false, this means that (0,1) is not a solution. Remember, a solution must satisfy all of the equations in the system.

C)

Let's see if (1,2) is a solution.

Start with the first equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is not true, this means that (1,2) is not a solution.

Let's see if (1,2) is a solution.

Start with the second equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is true, this means that (1,2) is a solution.

Since at least one of the equations of the system is false, this means that (1,2) is not a solution. Remember, a solution must satisfy all of the equations in the system.

D)

Let's see if (2,7) is a solution.

Start with the first equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is true, this means that (2,7) is a solution.

Let's see if (2,7) is a solution.

Start with the second equation.

Plug in and .

Evaluate and simplify the left side.

Evaluate and simplify the right side.

Since the equation is true, this means that (2,7) is a solution.

Since all of the equations of the system are true, this means that (2,7) is a solution

===============================================================

Answer:

So the solution is D) (2,7)
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