SOLUTION: I dont understand how I should solve these by factoring; x^2-5x+6=0, 2x^2-9x-5=0, 3x^2+5x-2=0, could someone please help me with them?

Question 151080: I dont understand how I should solve these by factoring; x^2-5x+6=0, 2x^2-9x-5=0, 3x^2+5x-2=0, could someone please help me with them?
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
1. x^2-5x+6=0

Factor
(x-3)(x-2)=0

Set each expression equal to 0 and solve
x-3=0
x=3

x-2=0
x=2

So x=2; 3
----------------------------------------------------------------------------
2.2x^2-9x-5=0

Factor
(2x+1)(x-5)=0

Set each expression equal to 0 and solve
2x+1=0
2x=-1
x=-1/2

x-5=0
x=5

So x=-1/2; 5
--------------------------------------------------------------------------
3. 3x^2+5x-2=0

Factor
(3x-1)(x+2)=0

Set each expression equal to 0 and solve
3x-1=0
3x=1
x=1/3

x+2=0
x=-2

So x=1/3; -2
RELATED QUESTIONS
Please help me. I am confused. How do I solve these by factoring? 3x^2 -2x = 0 and (answered by ankor@dixie-net.com)

Please help me with this.I'm not sure how to do this.I have to solve these by factoring: (answered by ankor@dixie-net.com)

how would i solve these using factoring :D . 1- (x - 2)(2x - 5) = 0 2- x^2 + (answered by edjones)

How would i solve these using factoring ? . 1- 5x^2 = 2x - 7x^2 2- 3x^2 + 6x... (answered by checkley71)

solve by factoring a) x^3-2x^2-5x+6=0 b) 3x^3+2X^2-8x+3=0 solve... (answered by Boreal)

Solve by factoring (please show work) {{{ x^2+5x+6=0 }}} and {{{ 2x^2-x-3=0 }}} (answered by Maths68)

I had to solve a quadratic equation by factoring and I recived it back as incorect. I... (answered by jim_thompson5910,MathLover1)

Solve For X. 5x^2 + 2 = 9x 5x^2-9x+2=0 (Divide everything by 5) x^2 + 2/5 -... (answered by jim_thompson5910)

Hi all, I was hoping someone could show me how to find: the indefinite intergral of f... (answered by algebrapro18)