Question 150869: Caleb and Drew are playing a game with a pair of dice. Caleb needs a sum of 5 or greater to win.What is his probability of winning on his next turn?
A. 5/6 B. 2/5 C. 1/6 D. 2/3
Found 2 solutions by jojo14344, stanbon:
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website! Okay, in order to get total of "5", the minimum Caleb needs to get on 1 dice is "4" and of course we'll based on the worst case scenario of getting the lowest number on the other dice, which is "1". (that total to "5" right?)
.
The probability of getting "4" or better is  . Why 3? It can be either 4, 5 or 6, that's why you put 3 possible numbers. Why 6? Of course you know there are 6 possible #'s right?
Now, for the other dice, being the smallest value "1", so the probability of getting this is  .
Therefore, if you add the 2 probabilities,  ----> 
Answer: "D"
Thank you,
Jojo
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Caleb and Drew are playing a game with a pair of dice. Caleb needs a sum of 5 or greater to win.What is his probability of winning on his next turn?
A. 5/6 B. 2/5 C. 1/6 D. 2/3
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The number of possible sums is 6x6 = 36
The sums below 5 are:
1+1, 1+2 ,1+3 ,2+1 ,2+2 ,3+1
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So there are 30 sums >= 5
P(sum >=5) = 30/36 = 5/6
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Cheers,
Stan H.
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