SOLUTION: solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1

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Question 1209190: solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1
Found 2 solutions by ikleyn, timofer:
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1
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From the second equation, express  y = 2a-1  and substitute it into first equation.
You will get

    3a^2 - 4(2a-1) = -1,

    3a^2 - 8a + 4 = -1,

    3a^2 - 8a + 5 = 0,


apply the quadratic formula

     =  = .


So, there are two options for "a": they are

    a =  =   and  a = 1.


Now find y for each value of "a", using y = 2a-1.

From this point, can you complete on your own ?



Answer by timofer(104)   (Show Source): You can put this solution on YOUR website!


, substitution for y


discriminant, just in case,




If a=1 then y=1.
If a=5/3 then ;
so (1,1) or ( 5/3, 7/3 ).

Check for any possible mistakes.
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