SOLUTION: The number of lemons a fruit seller bought in December was 30% more than in November. In January, he bought 50% less lemons than in December. If there were 3577 more lemons in Nove

Question 1192503: The number of lemons a fruit seller bought in December was 30% more than in November. In January, he bought 50% less lemons than in December. If there were 3577 more lemons in November than January, how many lemons did the fruit seller buy in November?
Found 2 solutions by Theo, greenestamps:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i get the following:

d = n + .3 * n = 1.3 * n
j = d - .5 * d = .5 * d
n = j + 3577

d = the number of melons bought in december.
j = the number of melons bought in january.
n = the number of melons bought in november.

since n = j + 3577 and j = .5 * d and d = 1.3 * n, then:
n = .5 * 1.3 * n + 3577
combine like terms to get:
n = .65 * n + 3577
subtract .65 * n from both sides of the equqtion to get:
.35 * n = 3577
solve for n to get:
n = 3577 / .35 = 10220.

since n = j + 3577, then j = n - 3577 = 10220 - 3577 = 6643.

since d = 1.3 * n, then d = 1.3 * 10220 = 13286.

you have:
d = 13286
j = 6643
n = 10220

d = 1.3 * n becomes 13286 = 1.3 * 10220 which becomes 13286 = 13286.
j = .5 * d becomes 6643 = .5 * 13286 which becomes 6643 = 6643.
n = j + 3577 becomes 10220 = 6643 + 3577 which becomes 10220 = 10220.

if the assumption are correct, then the solution is correct.
the solution is that the fruit seller bought 10220 lemons in november.

let me know if this was good.

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

x = # bought in November
1.30(x) = 1.3x = # bought in December (30% more then November)
.50(1.3x) = 0.65x = # bought in January (50% less than in December -- i.e., 50% as many)

The number bought in November is 3577 more than in January:

ANSWER: He bought 10220 lemons in November

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