SOLUTION: At a party, 1/3 of the guests drank only soda, and 2/5 of the guests drank only juice. If the remaining 16 guests had nothing to drink, then how many guests were at the party?

Question 1183841: At a party, 1/3 of the guests drank only soda, and 2/5 of the guests drank only juice. If the remaining 16 guests had nothing to drink, then how many guests were at the party?

Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!


1/3 + 2/5 = 5/15 + 6/15 = 11/15ths of the guests drank soda or orange juice.

That left 1 - 11/15 = 15/15 - 11/15 = 4/15 who had nothing to drink.

Let x represent the number of guests: 



Multiply both sides by the reciprocal 15/4:





There were 60 guests.

Edwin

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