SOLUTION: If sin A=6÷13 and sec B=13/6 then A+B is equal to Show solution without calculator 150° 90° 60° 45°

Question 1133682: If sin A=6÷13 and sec B=13/6 then A+B is equal to
Show solution without calculator
150°
90°
60°
45°
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

I will assume these angles are less than 90 degrees each; otherwise there are an infinite number of values for the sum of the measures of A and B.

sinA = 6/13 and secB = 13/6 --> sinA = 6/13 and cosB = 6/13.

In the first quadrant, if sinA = cosB, then A and B are complementary angles, so A+B = 90 degrees.
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