SOLUTION: A basketball team won 60% of the 55 games they played. What fraction of their games were lost? I�m just not sure Thank you

Question 1121704: A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
I�m just not sure
Thank you
Found 3 solutions by Theo, Alan3354, MathTherapy:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
if they won 60% of the games the played and they played 55 games, then they won .6 * 55 = 33 games.

since they can only win or lose, then all of the games they didn't win, they lost.

therefore, they had to lose 55 - 33 = 22 games.

33 wins and 22 losses totals 55 games.

33 / 55 = .6 = 60%.

22 / 55 = .4 = 40%.

60% wins and 40% losses translates into 33 wins and 22 loses.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
============
100% - 60% = 40%
Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!
A basketball team won 60% of the 55 games they played.
What fraction of their games were lost?
I�m just not sure
Thank you

What are you unsure about?
60% of games were won, so of games were LOST.
OR
60% of games were won, and
As the team won of the games, fraction lost =
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