SOLUTION: Benjamin had a sum of money. He spent $288 on a watch and 3/8 of the remainder of a belt. He had 2/5 of his money left in the end. What fraction of the money did he spend on th

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Question 1119763: Benjamin had a sum of money. He spent $288 on a watch and 3/8 of the remainder of a belt. He had 2/5 of his money left in the end.
What fraction of the money did he spend on the watch?
How much money did he have at first?

I have no idea how to tackle this question. Can someone advise how I would calculate?
Thanks in advance.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
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Benjamin had a sum of money. He spent $288 on a watch and 3/8 of the remainder of a belt. He had 2/5 of his money left in the end.
What fraction of the money did he spend on the watch?
How much money did he have at first?
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x, the original sum of money

Spent $288, and of what was present after spending the $288.
He then had dollars, after the two purchases.


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He had 2/5 of his money left in the end.
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Benjamin had a sum of money. He spent $288 on a watch and 3/8 of the remainder of a belt. He had 2/5 of his money left in the end.
What fraction of the money did he spend on the watch?
How much money did he have at first?

I have no idea how to tackle this question. Can someone advise how I would calculate?
Thanks in advance.
Correct answer: . 
Any other answer deserves to be thrown in the GARBAGE, which includes an equation by a person who responded to your math problem.
Let me show it to you: <====== GARBAGE
Let the original amount be A
Then after spending $288, he had A - 288 remaining
After spending of the remaining (A - 288), he had
Now, since in the end he had of the original amount remaining, we can say that:

16A = 5(5)(A - 288) -------- Cross-multiplying
16A = 25A - 25(288)
16A - 25A = - 25(288)
- 9A = - 25(288)
A, or amount he initially had was:
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