SOLUTION: There are two triples of positive integers (a,b,c and d,e,f) such that
a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of
abc-def.
Question 1106473: There are two triples of positive integers (a,b,c and d,e,f) such that
a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of
abc-def. Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website! There are two triples of positive integers (a,b,c and d,e,f) such that
a²+b²+c²=86 and d²+e²+f²=86. Evaluate the expression absolute value of
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Obviously, all are less than 10.
There's no algebraic solution, just trial and error.
There's no reason for me to do it.
You do it. Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website! .
1) 86 = 1^2 + 2^2 + 9^2
2) 86 = 5^2 + 5^2 + 6^2.
You do the rest.