SOLUTION: Write each fraction in simplest form. 42/55 Help me please

Question 106407: Write each fraction in simplest form.
42/55
Help me please
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: Reducing Fractions Calculator

In order to reduce , the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.

In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of and is AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

In other words, to reduce the fraction you do this

AMP Parsing Error of [(42/)/(55/)]: Invalid expression ')/(55/)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Plug in the numerator, denominator, and the GCF

AMP Parsing Error of [(42)/(55/)]: Invalid expression ')': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Now divide 42 by to get 42. This is now the new numerator.

Now divide 55 by to get 55. This is now the new denominator.

So

AMP Parsing Error of [(42/)/(55/)=42/55]: Invalid expression ')/(55/)=42/55': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

This means that reduces to

In other words,

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