SOLUTION: A B and C can clean a house in 2 hours
A can clean a house in 5 hours
B can clean a house in 6 hours
How long does it take A and C to clean a house?
My work so far:
A= 300/6
Algebra.Com
Question 1058019: A B and C can clean a house in 2 hours
A can clean a house in 5 hours
B can clean a house in 6 hours
How long does it take A and C to clean a house?
My work so far:
A= 300/60 min.
B= 360/60
C= x/60
Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Their rates of cleaning would look like:
[ 1 house cleaned ] / [ time to clean the house ]
Let = A's rate of cleaning
Let = B's rate of cleaning
Let = C's rate of cleaning
-----------------------------------
given:
(1)
(2)
(3)
-------------------------------
By substitution:
(1)
Multiply both sides by
(1)
(1)
(1)
----------------------
Let = time in hrs for A and C together to
clean a house
Multiply both sides by
A and C together will take 3 hrs to clean a house
----------------------
check answer:
Plug this result into (1)
(1)
(1)
(1)
(1)
(1)
OK
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.
I see that in solving joint work problems you are in very starting position.
There are introductory lessons on solving joint-work problems with detailed explanations in this site
- Using Fractions to solve word problems on joint work,
- Solving more complicated word problems on joint work,
- Selected joint-work word problems from the archive
Read them and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".
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