SOLUTION: if 1/x=a+b , 1/y=a-b, x+y=?
pls show me how to solve it thanks
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Question 1036064: if 1/x=a+b , 1/y=a-b, x+y=?
pls show me how to solve it thanks
Found 2 solutions by stanbon, fractalier:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if 1/x=a+b , 1/y=a-b, x+y=?
-------
Invert both sides to get:
x = 1/(a+b)
y = 1/(a-b)
-------
x + y = [(a-b)+(a+b)]/(a^2-b^2)
----
x+y = (2a)/(a^2-b^2)
----------------
Cheers,
Stan H.
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Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Given that
and
we are able to switch x with a+b and y with a-b...it takes two steps but it is perfectly proper...this gives us
and
so that
x + y =
Now to combine these, there is a shortcut, but let us just change both fractions to their common denominator (a+b)(a-b)...like this
==
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