SOLUTION: Can someone help me please?? thank you. Consider the points A(-2, 5), B(2, -3), C(8, 0), and P(4, 3). P is on the bisector of <ABC. Write an equation of the line in point-slope

Question 929360: Can someone help me please?? thank you.
Consider the points A(-2, 5), B(2, -3), C(8, 0), and P(4, 3). P is on the bisector of thanks !!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
A(-2, 5), B(2, -3), C(8, 0), and P(4, 3).

Find the slope of AB and BC.
AB:

BC:

AB and BC are perpendicular since their slopes are negative reciprocals.

The angle between the two lines is then 90 so a bisector would split the angle into 2 45 degree segments.
The line BC makes an angle with the x-axis determined by the slope.

Adding to this and then taking the tangent to find the slope,

Using the point slope form of a line with point B,

.
.
.

.
.
.
You could have also used point P and found the slope of BP.

Continuing the same way as shown previously.
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