SOLUTION: Please help to show or explain to me how to graph on a number line x^2 - 5x > or equal to -6; D = {reals}

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Question 77805This question is from textbook Alegbra 2 an incremental development
: Please help to show or explain to me how to graph on a number line
x^2 - 5x > or equal to -6; D = {reals} This question is from textbook Alegbra 2 an incremental development

Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
x^2 - 5x >= -6
x^2 - 5x + 6 >= 0
(x - 2)(x - 3) >= 0

x is in (-infinity, 2] and [3, infinity)


0........1........2........3........4........5
<----------|======|--------->

No, this solution is correct.
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.

The solutions by   @CubeyThePenguin  is INCORRECT.

I came to bring you the correct solution. 


    x^2 - 5x >= -6   ----------->


    x^2 - 5x + 6 >= 0


    (x-3*(x-2) >= 0


    ANSWER.  The solution set  is  (-oo,2] U [3,oo).


Ignore the post by @Penguine, since his plot is incorrect.



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