SOLUTION: evaluate the sum A = 1 + 3 + 5 + ... + 2009 + 2011
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Question 452664
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evaluate the sum A = 1 + 3 + 5 + ... + 2009 + 2011
Found 2 solutions by
CubeyThePenguin, MathTherapy
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Answer by
CubeyThePenguin(3113)
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1 + 3 + ... + 2011 = (1006)^2 = 1,012,036
Answer by
MathTherapy(10555)
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evaluate the sum A = 1 + 3 + 5 + ... + 2009 + 2011
Yet ANOTHER WRONG answer by the other person!
Correct answer:
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