.
Solve: 3 + |2y-1| ≥ 1. Graph the solution set on a number line.
~~~~~~~~~~~~~
The solution by @Penguin is INCORRECT.
I came to bring you a correct solution.
You start with this inequality
3 + |2y-1| >= 1.
Next you subtract the number 3 from both sides.
|2y-1| >= 1 - 3,
or
|2y-1| >= -2.
But the absolute value is ALWAYS NON-NEGATIVE number,
so the last inequality is valid FOR ANY VALUE of y.
ANSWER. The solution set is the ENTIRE NUMBER LINE from -oo to oo.
Solved, answered, explained and completed.
/////////////
Ignore the post by @Pinguin, since it is T O T A L L Y W R O N G.