SOLUTION: I have to evaluate this function:
g(t) = -3t^2-t; find g(t/3).
What I have so far is -3(t/3)^2 - t/3.
Is that correct so far? And I'm not even sure where to go from here.
Algebra.Com
Question 271968: I have to evaluate this function:
g(t) = -3t^2-t; find g(t/3).
What I have so far is -3(t/3)^2 - t/3.
Is that correct so far? And I'm not even sure where to go from here. Help please!
Thanks
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I have to evaluate this function:
g(t) = -3t^2-t; find g(t/3).
What I have so far is -3(t/3)^2 - t/3.
-------------------
That's a good start
= -3*(t^2/9) - t/3
= -t^2/3 - t/3
It can be rearranged into different versions
= (-1/3)*(t^2 + t)
= (-t/3)*(t+1)
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