SOLUTION: cant seem to solve this one.. i have to put it on a number line too x^2 + 2x

SOLUTION: cant seem to solve this one.. i have to put it on a number line too x^2 + 2x > 3 Thanks!

Question 263397: cant seem to solve this one.. i have to put it on a number line too
x^2 + 2x > 3
Thanks!
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
here is the original question

step 1 - subtract 3 to get

step 2 -factor to get

step 3 we need to create 3 number line graphs. Make sure the 0 marker is aligned in all three.
number line graph #1:
x+3> 0
this means open circle above -3 and then + signs to the right and - signs to the left.
number line graph #2:
x-1> 0
this means open circle above +1 and then + signs to the right and - signs to the left.
number line graph #3:
(x+3)(x-1) > 0
we place open circles above -3 and then +1.
To the left of -3, we have - signs for both lines. - x - = + so in the third number line place a + to the left of -3.
Between -3 and +1 we have different signs, so place a - sign on the third number line between -3 and +1.
To the right of +1, we have + signs for both lines. + x + = +, so in the third number line place a + to the right of +1.
we want where the signs are > 0 or the + regions.
Our final answer is
open circles above -3 and +1 and then arrow from the -3 to the left and arrow from the +1 to the right.
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