SOLUTION: I was wondering how to solve this problem. 4c=3d+3 c=d-1 4(d-1)=3d+3 = 4d-4=3d+3 subtract 3d to both sides d-4=3 Add 4 to both sides d=7 how do you post ?'s I

Question 179815This question is from textbook Algebra 1
: I was wondering how to solve this problem.

4c=3d+3
c=d-1 4(d-1)=3d+3 = 4d-4=3d+3 subtract 3d to both sides d-4=3 Add 4 to both sides d=7 how do you post ?'s

I got at least this far:
4(d-1)=3d+3
But now, I dont know if I'm soposed to find out what the variables are first or distribute. If I distribute, I dont kno how to distribute this equation. Can you help me? This question is from textbook Algebra 1

Found 2 solutions by stanbon, sup:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I was wondering how to solve this problem.
4c=3d+3
c=d-1
-----------------
Substitute and solve for "d":
4(d-1) = 3d + 3
4d - 4 = 3d + 3
d = 7
--------------
Since c = d-1, c = 7-1 = 6
==============================
Cheers,
Stan H.
Answer by sup(1) (Show Source): You can put this solution on YOUR website!

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