SOLUTION: A metalworker has a metal alloy that is 20% copper and another alloy that is 70% copper. How many kilograms of each alloy should the metalworker combine to create 80kg of a
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Question 1173513: A metalworker has a metal alloy that is 20% copper and another alloy that is 70% copper. How many kilograms of each alloy should the metalworker combine to create 80kg of a 60% copper alloy
Found 2 solutions by Solver92311, greenestamps:
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
\ =\ 0.6(80))
Solve for 
and then calculate 
John
My calculator said it, I believe it, that settles it
From
I > Ø
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
If a formal algebraic solution is not required, try this quick and easy method for solving 2-part "mixture" problems like this:
You are mixing 20% copper with 70% copper to get 60% copper.
60% is 40/50 = 4/5 of the way from 20% to 70%. (picture the three percentages on a number line, if it helps....)
That means 4/5 of the mixture is the higher percentage alloy.
ANSWER: 4/5 of 80kg, or 64kg, of 70% copper; the other 16kg of 20% copper.
CHECK:
.70(64)+.20(16) = 44.8+3.2 = 48
.60(80) = 48
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