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Tutors Answer Your Questions about Matrices-and-determiminant (FREE)
Question 4221: Hi, I asked a question on this set of equations a little while ago, but was wondering, could one use Cramers Rule to solve the following ..
a*4 + b*2 + c*9 + d * 7 = 21
a* 2 + b*5 + c*4 + d*4 = 11.5
a*6 + b*3 + c*5 + d*3 = 15.5
a * 8 + b * 4 + c * 6 + d * 6 = 22
If so, I would be most grateful if someone could show me how ... or get me started anyway :)
And could a general 'formula' be created using this rule to solve other similar sets of equations?
Click here to see answer by longjonsilver(2297)  |
Question 4223: Question 4221: Hi, I asked a question on this set of equations a little while ago, but was wondering, could one use Cramers Rule to solve the following ..
a*4 + b*2 + c*9 + d * 7 = 21
a* 2 + b*5 + c*4 + d*4 = 11.5
a*6 + b*3 + c*5 + d*3 = 15.5
a * 8 + b * 4 + c * 6 + d * 6 = 22
If so, I would be most grateful if someone could show me how ... or get me started anyway :)
And could a general 'formula' be created using this rule to solve other similar sets of equations?
---------------------------------
I asked this question a little while ago and was asked if a*4 was a to the power of 4 or a times 4. Its a times 4 ... and the same applies to all the other unknowns in the equation.
Click here to see answer by longjonsilver(2297)  |
Question 7050: I am having a hard time with a question, Complete the multiplication: AB
A=[ 6 0] B=[2 8]
[1.2 -3] [.6 3]
For the answer I chose
[6 0]
[1.2 -3]
The teacher said that I got the answer wrong so can someone tell me what the correct answer is because I keep comming to this same conclusion?
Click here to see answer by longjonsilver(2297)  |
Question 8462: The problem calls for the use of Matrices and Gaussian elimination with back-substituion to solve the system of the linear equation. I've worked the problem every way that I can think of, but I can't get half way past getting 1's to stair step down. (heh, best way I can describe it) The problem is
-x +3y-z =-4
2x +6z=14
-2x - y+ z=10
Click here to see answer by longjonsilver(2297)  |
Question 12425: Hello,
I would greatly appreciate it if a tutor could please verify my work for the below problem.
Find the determinant of the matrix B = [-1, 2, 3, 6, 0, 2, 3, 5, 1]. Matrix B is a 3x3 square matrix. The first column is -1, 2, 3. The second column is 6, 0, 2. The third column in 3, 5, 1. Row 1 is -1, 6, 3. Row 2 is 2, 0 , 5. Row 3 is 3, 2, 1.
I started by taking the numbers of the first row (-1, 6, 3) and multiplying them by the 2x2 matrix that remains when the row and column each number is in is deleted.
det B = -1[(0)(1)-(5)(2)] - 6[(2)(1)-(5)(3)] + 3[(2)(2)-(0)(3)]
det B = -1(0-10) - 6(2-15) + 3(4 - 0)
det B = -1(-10) - 6(-13) + 3(4)
det B = 10 + 78 + 12
det B = 100
In advance, thank you for your assistance!
Click here to see answer by khwang(438)  |
Question 12422: Hello,
I would appreciate it if a tutor could please help me verify my work for the below problem.
Find the determinant of matrix A = [-6, 4, 3, 5]. Matrix A is a 2x2 square matrix with -6 positioned above 4 and 3 positioned above 5.
det A = (-6)(5)-(3)(4)
det A = -30 - 12= -42
det A = -42
In advance, thank you for your assistance!
Click here to see answer by kchande(5)  |
Question 14532: You are playing 3-hole golf. On the first hole you score 1 under par, on the second hole you score 2 over par, and on the third hole you score 1 under par. What was your score for the game? (If you are at an even par your score is zero. In golf the total score is given as the number of strokes above or below par, expected score.)
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Click here to see answer by Alwayscheerful(414)  |
Question 16511: How do you go about writing a relection matrix of this given scenario?
"The vertices of quadrilateral ABCD are A(-3,2) B(0,3) C(4,-4) D(-2,-2) when it is reflected over the y-axis?"
Any help at this point would be greatly appreciated.
Click here to see answer by heeroic(1)  |
Question 18316: Please help me with this problem. Solve matrix Equation
[3 2] X= [1 0 2]
[1 1] X= [-3 1 4]
I think this might be no solution, but not quite sure.Since the dimension is 2 by 3.So please help me solve this. Thank you so much for your time.
( there are two X= because the problem looks weird when i don't place it there,suppose to be only one)
Truly,
Kat
Click here to see answer by venugopalramana(3286)  |
Question 18759: I have to solve this 4x4 matrix using Cramer's Rule:
4x + 0y + 3z - 2w = 2
3x + 1y + 2z - 1w = 4
1x - 6y - 2z + 2w = 0
2x + 2y + 0z - 1w = 1
Once I get to finding the determinants of the three 3x3 matrices, I am completly lost. Do you solve like a normal 3x3 and just multiply the determinent found by the number on the outside? After that is it simply repeating the same process for the other variables and adding the answers together?
Click here to see answer by venugopalramana(3286)  |
Question 19634: My question is.... I was wondering how to do the cramer rule on a 3x3. I have found a bunch of examples and stuff, but I want to know how in the world do you find the determinants of the D, Dx, Dy.and Dz. If you could just tell me how, that would be great.
Click here to see answer by venugopalramana(3286)  |
Question 20162: I have to solve a 4X4 matrix
w x y z
2 -2 -2 2 10
1 1 1 1 -5
3 1 -1 4 -2
1 3 -2 2 -6
Now I know I can flip row 2 and row 1
1 1 1 1 -5
2 -2 -2 2 10
3 1 -1 4 -2
1 3 -2 2 -6
Now I can slove the second row by mutiplying row1 one by -2 and adding row2 etc.
1 1 1 1 -5
0 -4 -4 0 20
0 -2 -7 1 13
0 2 -3 1 -1
Now I am stuck where do I go from here????
Click here to see answer by vidyamanohar(13)  |
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