SOLUTION: A stadium has 53,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in Section A equals the
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Question 994047: A stadium has 53,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in 1,134,500 from each sold-out event. How many seats does each section hold?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
A=x
B+C=x
2x=53,500
x=26,500 seats in section A, and that generates $662,500.
B+C=26,500
20B+15C=472,000, since the total from A and B/C must equal $1,134,500
-20B-20C= -530,000, multiplying the top equation by (-20)
-5C=-58,000
C=11,600 seats
Therefore B=14,900 seats
A generates 662,500
B generates 298,000
C generates 174,000
They add to 1134500
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