SOLUTION: Pls help: {{{ solve x > x^2}}}

Algebra.Com
Question 969615: Pls help:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
0> x^2 -x
I like the form x^2 - x <0
Factor out x
x(x-1) <0

x<0 doesn't work, since all squares are positive,
x-1 < 0; x< 1
That works until 0 is reached, so the interval that works is (0,1). When fractions under 1 are squared, they become less than the original number. (1/2) ^2= (1/4).
Note: While dividing by x at the beginning gives you the correct answer, it removes one other root from consideration, so move all the variables to one side.

RELATED QUESTIONS

Pls help... (answered by fractalier)
pls help solve for x... (answered by josgarithmetic)
Solve sin(2x) = sin(x/2)... (answered by Alan3354)
pls help me... (answered by greenestamps,josgarithmetic)
Pls. help me to solve this equation: Find the vertex of {{{y = 3x^2 + x -... (answered by Edwin McCravy)
Pls , help me to solve this problem" (2x^3+x^2)-(8x-4)=0 Thanks (answered by midwood_trail)
Pls. help me to solve this equation: Find the vertex of {{{y = 3x² + x -... (answered by Theo)
Can you pls. help: Solve the equation, making the bases the same... (answered by jsmallt9)
Please help me solve this equations pls. a.2x-4=6... (answered by solver91311)