SOLUTION: 2x₁+3x₂ =-2
x₁+2x₂+3x₃=0
-x₂-5x₃=1
Give the matrix equation associated with the system of equations below, and solve it by usin
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Question 950463: 2x₁+3x₂ =-2
x₁+2x₂+3x₃=0
-x₂-5x₃=1
Give the matrix equation associated with the system of equations below, and solve it by using the corresponding inverse mix.
What I've done so far.
2 3 0 [x] =-2
1 2 3 [y] =0
0 1 5 [z] =1
[x]=[2 3 0] ^-1.......[-2 ]
[y]=[1 2 3]............[ 0 ]
[z]=[0 1 5]...........[ 1 ]
I'm not sure if I'm doing it right. Please show me the steps. I'm currently working on it BTW. Thanks.
Found 2 solutions by Fombitz, Newb:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your third equation is
So the last row of the matrix should be 0 -1 -5.
Answer by Newb(4) (Show Source): You can put this solution on YOUR website!
Fombitz
Good catch for the first.
For the second part I got
Determinant: -14+15-0=1
M11=-7
M12=-15
M13=9
M21=-5
M22=-10
M23=6
M31=-1
M32=-2
M33=1
-7|15|9
5|-10|-6
-1|2|1
I don't understand the last part. Please clarify if you can. Thanks.
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