SOLUTION: solve the system -32+3z=4(x-2y), 4(x-2y-z)=-36, -2(2x+y)+2z=-12

Question 923558: solve the system -32+3z=4(x-2y), 4(x-2y-z)=-36, -2(2x+y)+2z=-12
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
-32+3z=4(x-2y), 4(x-2y-z)=-36, -2(2x+y)+2z=-12
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put the system of linear equations into standard form
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-32 + 3z = 4(x - 2y)
4(x - 2y - z) = -36
-2(2x + y) + 2z = -12
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-32 + 3z = 4x - 8y
4x - 8y - 4z = -36
-4x - 2y + 2z = -12
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-4x + 8y + 3z = 32
4x - 8y - 4z = -36
-4x - 2y + 2z = -12
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 3
y = 4
z = 4
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