SOLUTION: The values of K for which the system of equations x + y = 4 Kx + 2y + 3z = 1 2x + y + Kz = 5 does not have any solution

SOLUTION: The values of K for which the system of equations x + y = 4 Kx + 2y + 3z = 1 2x + y + Kz = 5 does not have any solution

Algebra.Com

Question 866744: The values of K for which the system of equations
x + y = 4
Kx + 2y + 3z = 1
2x + y + Kz = 5
does not have any solution
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
1x+1y+0z=4
kx+2y+3z=1
2x+1y+kz=5
k=-1 causes division by zero
so there is no solution

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