1 -1 1 5
2 3 -3 0
Add -2 times the first row to the second row:
1 -1 1 5
0 5 -5 -10
Multiply the second row by 1/5:
1 -1 1 5
0 1 -1 -2
Add the second row to the first:
1 0 0 3
0 1 -1 -2
This is as far as we can go. It translates into:
x = 3
y - z = -2 or y = z - 2
So there are an infinite number of solutions. The x must be 3 but the y and z values can be any numbers which fit either y - z = -2 or y = z - 2.One way to express the solution is: (3, z-2, z)