log(10p) = p×log(10) = p×(1) = p = 3.14159 = 3 + .14159

The characteristic is 3 and the mantissa is .14159

We look through the body of the log table and we find that .14159
is between the values of .1399 and .1430.  We see that .1399 is the
log of 1.38 and .1430 is the log of 1.39.  We want to know what 
.14159 is the log of.  So we say it is the log of x:

.1399   is the log of 1.38, which means 1.38 = 10.1399
.14159  is the log of x,    which means    x = 10.14159
.1430   is the log of 1.39  which means 1.39 = 10.1430

So we interpolate to find x:







.54516 = 

Multiply both sides by .01

.0054516 = x - 1.38

1.38545 = x, which equals 10.14159

log(10p) = 3 + .14159

Raising 10 to the power of both sides, that is, taking the antilog of
both sides, we have

10p = 103 + .14159

10p = 103×10.14159

10p = 1000×1.38545 = 1385.45

Answer = 1385.45

Edwin