SOLUTION: Solve by either elimination, substitution or Crammer's Rule. I am not sure how to do this problem since there is more than one # on the right side of the =. Please help. y=10-

Question 73181: Solve by either elimination, substitution or Crammer's Rule.
I am not sure how to do this problem since there is more than one # on the right side of the =. Please help.
y=10-2z-x
4x-y=2
-5+5z=4x+3y
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Rearrange the equations in the form ax+by+cz = d
y=10-2z-x
4x-y=2
-5+5z=4x+3y
-------------
x+y+2z = 10
4x-y+0z = 2
4x+3y-5z=-5
----------------
The "coefficient" matrix has determinant (5+24+0)-(-8+0-20)=57
The "x" matrix determinant is 62
The "y" matrix determinant is 134
The "z" matrix determinant is 187
---------
x=62/57
y=134/57
z=187/57
-----------
Using matrix multiplication (A^-1B) I get the same answer.
Cheer,
Stan H.
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